V05 - spring-mass oscillator (dynamic)
First the fundamentals, then the digital experiment — you answer the guiding questions at the end, with your own measured values at hand. A ready-made solution is deliberately not provided here.
Cover sheet
Name and matriculation number for this experiment’s report
Both appear on the PDF report and in the verification view behind the QR code. Enter them before you start with the fundamentals.
One cover sheet, one report. If the name or the matriculation number is changed later, this experiment starts over: measured values, answers and assignments are deleted and the apparatus is set up anew.
Chapter 1: The spring and the restoring force
Why gravity no longer matters once it oscillates
Pull on a helical spring and it pulls back — the further it is stretched, the more strongly. In 1676 Robert Hooke put this into a sentence that still holds today: The force is proportional to the deflection.
The proportionality factor C means spring constant and is measured in N/m. Determining it is the goal of this part of the experiment — here by way of time instead of distance.
Figure: when a mass hangs on the spring, a new Restoration is established. Everything that follows is measured from it.
That is the decisive step: in the rest position, weight and spring force already balance each other. Displace the mass from there and all that remains is the additional spring force — and that always points back towards the rest position. Gravity only shifts the rest position; it does not drive the oscillation.
Three masses, two letters — a trap
In this module M is the attached mass and mF is the mass of the spring.
The lower-case m is reserved for the slope of the regression line — that is its traditional name and the one the tool uses. The measurement column of the attached mass is nevertheless labelled “m / kg” at the test rig, for historical reasons.
Chapter 2: The oscillating mass
From the restoring force to the period — in five steps
Pull the mass out of its rest position and let go, and it oscillates. Click through it step by step; the drawing highlights what is being discussed.
-
Restoring force. x is measured from the rest position. The additional spring force is proportional to it and directed against it.
-
Newton. Force equals mass times acceleration:
-
Rearranged — the equation of harmonic oscillation:
-
The comparison yields the angular frequency:
-
And with T = 2π/ω the period:
Gravitational acceleration does not appear
The formula contains no g. A spring pendulum oscillates on the Moon just as fast as on Earth — the rest position simply lies elsewhere.
Chapter 3: The spring oscillates too
Why a third of the spring mass belongs in the formula
The derivation in Chapter 2 pretends the spring is massless. It is not — and its mass moves along. But not equally everywhere: the coils close to the suspension stay almost still, the lowest ones travel the full path of the mass.
Figure: the arrows show how far the coils move — from zero at the top to the full excursion at the bottom.
If you add up the kinetic energy of all the coils, the spring behaves as if a third of its mass were attached at its end as well. The period is therefore:
For heavy loads this hardly matters, for light ones it very much does. And it has a nice consequence: anyone who records a series of measurements over several masses can obtain from it not only the spring constant but also the mass of the spring — without ever putting it on a balance. How, that is the last key question of this part of the experiment.
Chapter 4: Why linearise at all?
Why a straight line is worth more than a curve
Each measurement scatters. One Straight line can be determined robustly and transparently from scattered data points, whereas fitting a curved relationship is more difficult. A nonlinear relationship is therefore linearised by choosing suitable variables for the axes. The quantity being determined is then contained in the Increase or in Axle section the straight line.
In this form the formula from Chapter 3 is not linear: the period sits under a square root. The test bench's example series shows it:
Figure: period against the attached mass M, calculated with example values for spring and spring mass — your test bench draws its own for each session. The curve rises like a square root, steeply at first and then ever more gently; no straight line fits anywhere.
Before plotting, the formula must therefore be rearranged — the supplementary questions call it “juggling the formulas a little”.
Chapter 5: What does linear regression achieve?
Slope and intercept — and when they mean something
Linear regression determines that straight line y = m·x + cthat best fits your measurement points. Slope m and intercept c only carry a physical meaningif you derive the axes from the basic equation of the experiment. That choice is yours to make.
A word on naming: what the supplementary questions and the lab instructions call y-intercept is called here and in the evaluation tool c — both mean the value of the line at the position x = 0.
Watch the intercept: it contains the co-oscillating spring mass from Chapter 3. Here it is not a nuisance term but a second measurement result — an intercept close to zero would not be a good sign but a hint at an error.
The experiment
Record and evaluate a series of measurements — on the test-rig page
Attach the intended masses one after another, deflect the spring and measure the period — over many oscillations so that the stopwatch error stays small.
A button then takes you straight on to station 8, the guiding questions.
Your evaluation
Regression parameters
Questions
Answer them with your own measured values — the answers go into the report
The oscillating pendulum, once more
You know the drawing from Chapters 2 and 3. Now the labels are missing: drag them to the right place — with the mouse, by tapping, or by first tapping a building block and then a field.
Task: Name the three quantities on the oscillating pendulum.
A look at the arrows to the left of the spring helps with the third label.
Questions on the dynamic determination
-
Which quantities do you have to plot against each other in a diagram in order to perform a linear regression? (Careful: here you have to juggle the formulas a little.)
-
What is the relation between the spring constant you are looking for and the regression parameters you determined, that is, slope and intercept?
-
One of the two regression parameters is not needed for the spring constant at all — but it can be used to determine the mass of the spring. How does the spring mass influence the period, and how do you get at it through the regression?
Your answers are stored locally and are transferred into your Preparation report taken over. There is no automatic evaluation — discuss your thoughts in the lab and in the colloquium.
Calculating the quantities you are after
Finally, complete the evaluation: for each quantity you are after, first state the relationship symbolically and then evaluate it with your own regression parameters.
-
Spring constant C
N/m -
Spring mass m_F
kg
There is no automatic assessment here either. Both entries go into your preparation report — so that in the end it contains not only the approach but also the result.
Preparation report
Series of measurements, diagram and your answers as a PDF
The PDF contains your series of measurements, the diagram with the regression line, the calculated parameters and your answers to the guiding questions — plus a QR code for verifying the report.
Checking the measurement status …
Further reading
- Walcher, W.: Praktikum der Physik 8th edition, Teubner, Wiesbaden 2004
- Schenk, W.; Kremer, F. (eds.): Physikalisches Praktikum 14th edition, Springer Spektrum, Wiesbaden 2014
- Demtröder, W.: Experimentalphysik 1: Mechanik und Wärme 9th edition, Springer Spektrum, Berlin/Heidelberg 2021
The titles lead to the publisher's page; the full text is available via the university network.